Python 打印左移数字的方阵程序

编写一个 Python 程序，使用 for 循环打印左移数字的方阵。

rows = int(input("Enter Square of Left Shift Numbers Rows = "))

print("====The Square Pattern of Left Shift Numbers====")

for i in range(1, rows + 1):
    for j in range(i, rows + 1):
        print(j, end = ' ')
    for k in range(1, i):
        print(k, end = ' ')
    print()

这是另一种编写 Python 程序以打印左移数字方阵的方法。

rows = int(input("Enter Square of Left Shift Numbers Rows = "))

print("====The Square Pattern of Left Shift Numbers====")

for i in range(1, rows + 1):
    j = i
    for k in range(1, rows + 1):
        print(j, end = ' ')
        j = j + 1
        if j > rows:
            j = 1
    print()

Enter Square of Left Shift Numbers Rows = 8
====The Square Pattern of Left Shift Numbers====
1 2 3 4 5 6 7 8 
2 3 4 5 6 7 8 1 
3 4 5 6 7 8 1 2 
4 5 6 7 8 1 2 3 
5 6 7 8 1 2 3 4 
6 7 8 1 2 3 4 5 
7 8 1 2 3 4 5 6 
8 1 2 3 4 5 6 7 

这个 Python 示例 使用 while 循环从上到下显示左移数字的方阵。

rows = int(input("Enter Square of Left Shift Numbers Rows = "))

print("====The Square Pattern of Left Shift Numbers====")

i = 1

while(i <= rows):
    j = i
    while(j <= rows):
        print(j, end = ' ')
        j = j + 1
    k = 1
    while(k < i):
        print(k, end = ' ')
        k = k + 1
    print()
    i = i + 1

Enter Square of Left Shift Numbers Rows = 9
====The Square Pattern of Left Shift Numbers====
1 2 3 4 5 6 7 8 9 
2 3 4 5 6 7 8 9 1 
3 4 5 6 7 8 9 1 2 
4 5 6 7 8 9 1 2 3 
5 6 7 8 9 1 2 3 4 
6 7 8 9 1 2 3 4 5 
7 8 9 1 2 3 4 5 6 
8 9 1 2 3 4 5 6 7 
9 1 2 3 4 5 6 7 8