Python 程序计算数组中的奇数和偶数个数

编写一个 Python 程序，使用 for 循环 range 计算数组中的奇数和偶数个数。if 条件 (if (evenOddArr[i] % 2 == 0)) 检查数组项是否能被二整除。如果为 True，我们将偶数数组计数加一；否则，将奇数数组计数加一。

# Using For loop

import numpy as np

evenOddArr = np.array([10, 99, 22, 50, 77, 22, 112, 19])
print("The List of Numbers in evenOddArr Array = ", evenOddArr)

evenArrCount = 0
oddArrCount = 0

for i in range(len(evenOddArr)):
    if (evenOddArr[i] % 2 == 0):
        evenArrCount = evenArrCount + 1
    else:
        oddArrCount = oddArrCount + 1

print("The Count of Even Numbers in evenOddArr Array = ", evenArrCount)
print("The Count of Odd Numbers in evenOddArr Array  = ", oddArrCount)

Python 程序计算数组中的奇数和偶数个数

在此示例中，我们使用了 numpy 的 mod 和 remainder 函数来检查每个项除以二的余数是否为零。

# using Numpy mod and remainder

import numpy as np

evenArr = np.array([4, 29, 88, 5, 0, 11, 17, 18, 7, 44, 9, 89])
evenArrCount = evenArrCount1 = evenArrCount2 = 0
oddArrCount = oddArrCount1 = oddArrCount2 = 0

for i in evenArr:
    if (i % 2 == 0):
        evenArrCount = evenArrCount + 1
    else:
        oddArrCount = oddArrCount + 1

print("The Count of Even Numbers in evenOddArr Array = ", evenArrCount)
print("The Count of Odd Numbers in evenOddArr Array  = ", oddArrCount)

print("\n=== Using mod function===")
for i in evenArr:
    if (np.mod(i, 2) == 0):
        evenArrCount1 = evenArrCount1 + 1
    else:
        oddArrCount1 = oddArrCount1 + 1
        
print("The Count of Even Numbers in evenOddArr Array = ", evenArrCount1)
print("The Count of Odd Numbers in evenOddArr Array  = ", oddArrCount1)

print("\n=== Using remainder function===")
for i in evenArr:
    if (np.remainder(i, 2) == 0):
        evenArrCount2 = evenArrCount2 + 1
    else:
        oddArrCount2 = oddArrCount2 + 1
print("The Count of Even Numbers in evenOddArr Array = ", evenArrCount2)
print("The Count of Odd Numbers in evenOddArr Array  = ", oddArrCount2)

计算 Numpy 数组中的奇偶数个数输出。

The Count of Even Numbers in evenOddArr Array =  5
The Count of Odd Numbers in evenOddArr Array  =  7

=== Using mod function===
The Count of Even Numbers in evenOddArr Array =  5
The Count of Odd Numbers in evenOddArr Array  =  7

=== Using remainder function===
The Count of Even Numbers in evenOddArr Array =  5
The Count of Odd Numbers in evenOddArr Array  =  7

编写一个程序，使用 While 循环计算 Numpy 数组中的奇偶数。

# Using while loop
import numpy as np
evenOddArr = np.array([4, 15, 19, 22, 9, 18, 140])
i = 0
evenArrCount = 0
oddArrCount = 0
while (i < len(evenOddArr)):
    if (np.equal(evenOddArr[i] % 2, 0)):
        evenArrCount = evenArrCount + 1
    else:
        oddArrCount = oddArrCount + 1
    i = i + 1

print("The Count of Even Numbers in evenOddArr Array = ", evenArrCount)
print("The Count of Odd Numbers in evenOddArr Array  = ", oddArrCount)

使用 While 循环计算 Python Numpy 数组中的奇偶数个数输出

The Count of Even Numbers in evenOddArr Array =  4
The Count of Odd Numbers in evenOddArr Array  =  3

在此 numpy 数组 示例中，我们创建了一个 (CountEvenOddNumbers(evenOddArr)) 函数，该函数返回奇偶数计数。

# Uisng Functions
import numpy as np
def CountEvenOddNumbers(evenOddArr):
    evenArrCount = 0
    oddArrCount = 0
    for i in evenOddArr:
        if (np.remainder(i, 2) == 0):
            evenArrCount = evenArrCount + 1
        else:
            oddArrCount = oddArrCount + 1

    return evenArrCount, oddArrCount

evenOddArr = np.array([11, 88, 15, 122, 140, 17, 10, 48, 35, 64])
even, odd = CountEvenOddNumbers(evenOddArr)
print("The Count of Even Numbers in evenOddArr Array = ", even)
print("The Count of Odd Numbers in evenOddArr Array  = ", odd)

使用函数计算 Numpy 数组中的奇偶数个数输出

The Count of Even Numbers in evenOddArr Array =  6
The Count of Odd Numbers in evenOddArr Array  =  4