Python 程序检查一个数是否为Pronic数

编写一个Python程序，使用while循环检查一个数是否为Pronic数。例如，如果一个数等于两个连续数的乘积，那么它就是Pronic数，意味着 number = n(n + 1)。

在此Python程序中，i值从零迭代到该数的平方根，并检查任何两个连续数的乘积是否等于实际数字。如果为True，则标志值变为一，break语句将退出循环。如果标志等于一，则它是一个Pronic数。

import math

Number = int(input("Enter the Number to Check Pronic Number = "))

i = 0
flag = 0

while i <= (int) (math.sqrt(Number)):
    if Number == i * (i + 1):
        flag = 1
        break
    i = i + 1

if flag == 1:
    print("\n%d is a Pronic Number." %Number)
else:
    print("%d is Not a Pronic Number." %Number)

Python程序使用for循环检查给定的数是否为Pronic数。 

Number = int(input("Enter the Number = "))

flag = 0

for i in range(Number + 1):
    if Number == i * (i + 1):
        flag = 1
        break

if flag == 1:
    print("\n%d is a Pronic Number." %Number)
else:
    print("%d is Not a Pronic Number." %Number)

Enter the Number = 42

42 is a Pronic Number.

Enter the Number = 55
55 is Not a Pronic Number.

这个Python 程序有助于使用函数来查找一个数是否为Pronic数。

def pronicNumber(Number):
    flag = 0
    for i in range(Number + 1):
        if Number == i * (i + 1):
            flag = 1
            break
    return flag
        
Number = int(input("Enter the Number to Check Pronic = "))

if pronicNumber(Number) == 1:
    print("\n%d is a Pronic Number." %Number)
else:
    print("%d is Not." %Number)

Enter the Number to Check Pronic = 52
52 is Not.

Enter the Number to Check Pronic = 72

72 is a Pronic Number.