C语言中的pow函数

C语言中的POW函数用于计算指定值或数字的幂。例如，如果x是基值，2是指数，则pow(x, 2) = x²，该函数的语法如下。

double pow(double base, double Exponent);

• 请在此指定基值和指数值或幂。

C语言pow函数示例

POW函数用于返回给定数字的幂。在此程序中，我们将使用此方法和printf语句计算正值和负值的幂并显示输出。

#include <stdio.h>
#include <math.h>

int main()
{
  int result1; 
  double result2, result3, result4, result5;
   
  result1 = pow(5, 3);
  printf("\n The Final result of %d Power %d = %d ", 5, 3, result1);
  
  result2 = pow(2, 0);
  printf("\n The Final result of %d Power %d = %f ", 2, 0, result2);
  
  result3 = pow(0, 2);
  printf("\n The Final result of %d Power %d = %f ", 0, 2, result3);
  
  result4 = pow(-2, 3);
  printf("\n The Final result of %d Power %d = %f ", -2, 3, result4);
  
  result5 = pow(3, -4);
  printf("\n The Final result of %d Power %d = %f ", 3, -4, result5);
  
  return 0;
}

pow示例2

此程序要求用户输入自己的基值和指数值。然后，math pow将计算用户指定值的幂。

#include <stdio.h>
#include <math.h>

int main()
{
  int result, base, exponent;
  
  printf("\n Please Enter the Base and Exponent Values : \n ");
  scanf("%d %d", &base, &exponent);
  
  result = pow(base, exponent);
  
  printf("\n The Final result of %d Power %d = %d ", base, exponent, result);
  
  return 0;
}

 Please Enter the Base and Exponent Values :  
 2
 5

 The Final result of 2 Power 5 = 32