Go 程序查找奇数之和

这个 Go 程序通过 for 循环迭代 1 到 n 来查找从 1 到 n 的奇数之和。在循环中，if 语句过滤奇数并将总和添加到奇数总和中。

package main

import "fmt"

func main() {

    var oddnum, Oddtotal int

    fmt.Print("Enter the Number to find Odd Sum = ")
    fmt.Scanln(&oddnum)

    Oddtotal = 0
    fmt.Println("List of Odd Numbers from 1 to ", oddnum, " are = ")
    for x := 1; x <= oddnum; x++ {
        if x%2 != 0 {
            fmt.Print(x, "\t")
            Oddtotal = Oddtotal + x
        }
    }
    fmt.Println("\nSum of Odd Numbers from 1 to ", oddnum, " = ", Oddtotal)
}

Enter the Number to find Odd Sum = 10
List of Odd Numbers from 1 to  10  are = 
1       3       5       7       9
Sum of Odd Numbers from 1 to  10  =  25

Golang 程序查找奇数之和。

在此程序中，我们修改了 for 循环，使其从 1 开始，并以 2 为增量来计算奇数之和。

package main

import "fmt"

func main() {

    var oddnum, Oddtotal int

    fmt.Print("Enter the Number to find Odd Sum = ")
    fmt.Scanln(&oddnum)

    Oddtotal = 0
    fmt.Println("List of Odd Numbers from 1 to ", oddnum, " are = ")
    for x := 1; x <= oddnum; x = x + 2 {
        fmt.Print(x, "\t")
        Oddtotal = Oddtotal + x
    }
    fmt.Println("\nSum of Odd Numbers from 1 to ", oddnum, " = ", Oddtotal)
}

Enter the Number to find Odd Sum = 25
List of Odd Numbers from 1 to  25  are = 
1       3       5       7       9       11      13      15      17      19      21  23       25
Sum of Odd Numbers from 1 to  25  =  169

这个 程序 计算从 min 到 max 的奇数之和。在这里，我们使用了一个额外的 if 语句来将用户输入的奇数值（如果有偶数值）加 1 以保持为奇数。

package main

import "fmt"

func main() {

    var Oddmin, Oddmax, Oddtotal int

    fmt.Print("Enter the Minimum Odd Number = ")
    fmt.Scanln(&Oddmin)
    fmt.Print("Enter the Maximum Odd Number = ")
    fmt.Scanln(&Oddmax)

    if Oddmin%2 == 0 {
        Oddmin++
    }

    Oddtotal = 0
    fmt.Println("Odd Numbers from ", Oddmin, " to ", Oddmax, " = ")
    for x := Oddmin; x <= Oddmax; x = x + 2 {
        fmt.Print(x, "\t")
        Oddtotal = Oddtotal + x
    }
    fmt.Println("\nSum of Odd Numbers from ", Oddmin, " to ", Oddmax, " = ", Oddtotal)
}

Enter the Minimum Odd Number = 10
Enter the Maximum Odd Number = 50
Odd Numbers from  11  to  50  = 
11      13      15      17      19      21      23      25      27      29      31  33       35      37      39      41      43      45      47      49
Sum of Odd Numbers from  11  to  50  =  600

它与第一个奇数之和示例相同。但是，它计算的是最小和最大限制之间的奇数和。

package main

import "fmt"

func main() {

    var Oddmin, Oddmax, Oddtotal int

    fmt.Print("Enter the Minimum Odd Number = ")
    fmt.Scanln(&Oddmin)
    fmt.Print("Enter the Maximum Odd Number = ")
    fmt.Scanln(&Oddmax)

    Oddtotal = 0
    fmt.Println("Odd Numbers from ", Oddmin, " to ", Oddmax, " = ")
    for x := Oddmin; x <= Oddmax; x++ {
        if x%2 != 0 {
            fmt.Print(x, "\t")
            Oddtotal = Oddtotal + x
        }
    }
    fmt.Println("\nSum of Odd Numbers from ", Oddmin, " to ", Oddmax, " = ", Oddtotal)
}