Go 程序查找偶数之和

编写一个 Go 程序，计算从 1 到 n 的偶数之和。它使用 for 循环在 1 和 n 之间迭代。循环内部，if 语句过滤偶数并将偶数累加到总和中。

package main

import "fmt"

func main() {

    var evnum, eventotal int

    fmt.Print("Enter the Number to find Even Sum = ")
    fmt.Scanln(&evnum)

    eventotal = 0
    fmt.Println("List of Even Numbers from 1 to ", evnum, " are = ")
    for x := 1; x <= evnum; x++ {
        if x%2 == 0 {
            fmt.Print(x, "\t")
            eventotal = eventotal + x
        }
    }
    fmt.Println("\nSum of Even Numbers from 1 to ", evnum, " = ", eventotal)
}

Enter the Number to find Even Sum = 10
List of Even Numbers from 1 to  10  are = 
2       4       6       8       10
Sum of Even Numbers from 1 to  10  =  30

Golang 程序查找偶数之和

在此 Golang 程序中，我们修改了 for 循环并计算偶数之和。

package main

import "fmt"

func main() {

    var evnum, eventotal int

    fmt.Print("Enter the Number to find Even Sum = ")
    fmt.Scanln(&evnum)

    eventotal = 0
    fmt.Println("List of Even Numbers from 1 to ", evnum, " are = ")
    for x := 2; x <= evnum; x = x + 2 {
        fmt.Print(x, "\t")
        eventotal = eventotal + x
    }
    fmt.Println("\nSum of Even Numbers from 1 to ", evnum, " = ", eventotal)
}

Enter the Number to find Even Sum = 20
List of Even Numbers from 1 to  20  are = 
2       4       6       8       10      12      14      16      18      20
Sum of Even Numbers from 1 to  20  =  110

此 Go 程序计算从最小值到最大值的偶数之和。在这里，我们使用了一个额外的 if 语句来确保用户输入的值是偶数，方法是递增奇数值。

package main

import "fmt"

func main() {

    var evenmin, evenmax, eventotal int

    fmt.Print("Enter the Minimum Even Number = ")
    fmt.Scanln(&evenmin)
    fmt.Print("Enter the Maximum Even Number = ")
    fmt.Scanln(&evenmax)

    if evenmin%2 != 0 {
        evenmin++
    }

    eventotal = 0
    fmt.Println("Even Numbers from ", evenmin, " to ", evenmax, " = ")
    for x := evenmin; x <= evenmax; x = x + 2 {
        fmt.Print(x, "\t")
        eventotal = eventotal + x
    }
    fmt.Println("\nSum of Even Numbers from ", evenmin, " to ", evenmax, " = ", eventotal)
}

Enter the Minimum Even Number = 30
Enter the Maximum Even Number = 50
Even Numbers from  30  to  50  = 
30      32      34      36      38      40      42      44      46      48      50
Sum of Even Numbers from  30  to  50  =  440

这与第一个偶数之和示例相同。但是，此 go 示例计算了 min 和 max 限制之间的总和。

package main

import "fmt"

func main() {

    var evenmin, evenmax, eventotal int

    fmt.Print("Enter the Minimum Even Number = ")
    fmt.Scanln(&evenmin)
    fmt.Print("Enter the Maximum Even Number = ")
    fmt.Scanln(&evenmax)

    eventotal = 0
    fmt.Println("Even Numbers from ", evenmin, " to ", evenmax, " = ")
    for x := evenmin; x <= evenmax; x++ {
        if x%2 == 0 {
            fmt.Print(x, "\t")
            eventotal = eventotal + x
        }
    }
    fmt.Println("\nSum of Even Numbers from ", evenmin, " to ", evenmax, " = ", eventotal)
}