C++ 程序查找偶数之和

编写一个 C++ 程序来查找从 0 到 n 的偶数之和。此 C++ 程序允许您输入最大数。接下来，我们使用 for 循环 (for(number = 1; number <= maximum; number++)) 来迭代从 1 到 maximum 的数字。我们在循环中使用 If 条件来检查数字 % 2 是否等于 0。如果为真，则将该数字添加到 sum 值 (sum = sum + number;) 中，并打印该数字作为偶数。

#include<iostream>
using namespace std;

int main()
{
	int number, maximum, sum = 0;
	
	cout << "\nPlease Enter the Maximum Limit for Even Numbers  =  ";
	cin >> maximum;	
	
	cout <<"\nEven Numbers between 0 and " << maximum << " = ";
	for(number = 1; number <= maximum; number++)
	{
  		if ( number % 2 == 0 ) 
		{
  			cout << number << " ";
			sum = sum + number;
		}
	}
	
	cout << "\nThe Sum of All Even Numbers upto " << maximum << " = " << sum;
	
 	return 0;
}

Please Enter the Maximum Limit for Even Numbers  =  20

Even Numbers between 0 and 20 = 2 4 6 8 10 12 14 16 18 20 
The Sum of All Even Numbers upto 20 = 110

C++ 程序查找偶数之和 示例 2

在此 C++ 程序中计算偶数之和，我们修改了 for 循环 (for(number = 2; number <= maximum; number = number + 2)) 以删除 If 语句。如您所见，我们将数字增加了 2（而不是 1 number++）。我们知道，从 2 开始，每次增加 2 的数字都将是偶数。因此，我们将该数字添加到 sum 中，并打印 sum 作为结果。

#include<iostream>
using namespace std;

int main()
{
	int number, maximum, sum = 0;
	
	cout << "\nPlease Enter the Maximum Limit for Even Numbers  =  ";
	cin >> maximum;	
	
	cout <<"\nEven Numbers between 0 and " << maximum << " = ";
	for(number = 2; number <= maximum; number = number + 2)
	{		
		sum = sum + number;
		cout << number << " ";
	}
	
	cout << "\nThe Sum of All Even Numbers upto " << maximum << " = " << sum;
	
 	return 0;
}

Please Enter the Maximum Limit for Even Numbers  =  30

Even Numbers between 0 and 30 = 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 
The Sum of All Even Numbers upto 30 = 240

此 C++ 偶数之和示例允许用户输入最小值和最大值。接下来，它将计算从最小值到最大值之间的偶数之和。

#include<iostream>
using namespace std;

int main()
{
	int number, minimum, maximum, sum = 0;
	
	cout << "\nPlease Enter the Minimum Limit for Even Numbers  =  ";
	cin >> minimum;	
	
	cout << "\nPlease Enter the Maximum Limit for Even Numbers  =  ";
	cin >> maximum;	
	
	cout <<"\n\nEven Numbers between  " << minimum << " and " << maximum << " = ";
	for(number = minimum; number <= maximum; number++)
	{		
		if ( number % 2 == 0 ) 
		{
  			cout << number << " ";
			sum = sum + number;
		}
	}
	
	cout << "\nThe Sum of All Even Numbers from " << minimum << " to " << maximum << " = " << sum;
	
 	return 0;
}