C++ 检查完美数程序

编写一个C++程序来检查完美数，并附带一个示例。任何数都可以是完美的，如果它的所有因子（不包括数字本身）之和等于该数字。例如，6可以被1、2、3整除（不包括6），1+2+3=6。因此，6是一个完美数。

在此C++完美数示例中，我们使用for循环（for(i = 1 ; i < number ; i++))从1迭代到number。我们使用if条件（if(number % i == 0))来检查数字是否能被循环值整除且余数为0。如果为真，则将该值加到总和中。最后，我们使用If条件（if(number == sum))来检查数字是否等于总和，并打印结果。

#include<iostream>

using namespace std;

int main()
{
	int number, i, sum = 0;
	
	cout << "Please Enter the Number to check for Perfect  =  ";
	cin >> number;
	
	for(i = 1 ; i < number ; i++)
	{
		if(number % i == 0)
		{
			sum = sum + i;
		}
	}
			
	if(number == sum)
	{
		cout << number << " is a Perfect Number";
	}
	else
	{
		cout << number << " is Not a Perfect Number";
	}
 	return 0;
}

使用while循环检查完美数的C++程序

#include<iostream>

using namespace std;

int main()
{
	int number, i = 1, sum = 0;
	
	cout << "Please Enter the Number to check for Perfect  =  ";
	cin >> number;
	
	while( i < number )
	{
		if(number % i == 0)
		{
			sum = sum + i;
		}
		i++;
	}
			
	if(number == sum)
	{
		cout << number << " is a Perfect Number";
	}
	else
	{
		cout << number << " is Not a Perfect Number";
	}
 	return 0;
}

Please Enter the Number to check for Perfect  =  496
496 is a Perfect Number

C++程序打印1到N之间的完美数

此程序完美数示例允许用户输入最小值和最大值。然后，它打印最小和最大值之间的完美数。

#include<iostream>

using namespace std;

int main()
{
	int minimum, maximum, number, i, sum;
	
	cout << "Enter Minimum and Maximum to find Perfect Numebrs =  ";
	cin >> minimum >> maximum;
	
	cout << "\nPerfect Numbers Between " << minimum << " and " << maximum << " = ";
	for(number = minimum; number <= maximum; number++)
	{
		for(i = 1, sum = 0; i < number ; i++)
		{
			if(number % i == 0)
			{
				sum = sum + i;
			}
		}
		if(number == sum) 
		{
			cout << number << " ";
		}
	}
	
 	return 0;
}

Enter Minimum and Maximum to find Perfect Numebrs =  
1
1000

Perfect Numbers Between 1 and 1000 = 6 28 496